HOW TO CALCULATE KVAR CAPACITY FOR CAPACITOR IN CASE OF POWER FCTOR IMPROVEMENT
5 KW 3 phase induction motor has a power factor of 0.7 lagging. A bank of capacitors is connected in delta across the supply terminals and power factor raised to 0.9 lagging.
Determined the of its capacitors rating connected in each phase.
A given data
power=5KW
COSΘ1=0.7
COSΘ2=0.9
WE HAVE THE EQUATION
KVAR=P(TANΘ1- TANΘ2) ........ equation 1
FIND
cos-1 (0.7) = 45.57
cos-1 (0.9) = 25.84
TANΘ1=TAN(45.57)
TANΘ1=1.020
TANθ2=TAN(25.84)
TANθ2=0.49
put this value in the equation 1
KVAR =5(1.020-0.49)
KVAR =2.65 KVAR
KVAR =2.65/3
= 0.88 rating capacitor connected in each phase to raised the power factor from 0.7 to 0.9
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